SIN (x+pi/6)= – căn3 /2

Ta có: \(\sin (x+\dfrac{\pi}{6})= – {\dfrac{\sqrt{3}}{ 2}}\)
\(\Rightarrow \left\{ \begin{array}{l} x+\dfrac{\pi}{6}=-\dfrac{\pi}{3}+k2\pi \\ x+\dfrac{\pi}{6}=\pi+\dfrac{\pi}{3}+k2\pi \end{array} \right .\)\(\Rightarrow \left\{ \begin{array}{l} x=-\dfrac{\pi}{2}+k2\pi \\ x=\dfrac{7\pi}{6}+k2\pi \end{array} \right .\) \((k\in\mathbb Z)\).